The nth term of a sequence is 3n^2-1a) Find the second term of the sequenceb) Find the fifth term of the sequence
Accepted Solution
A:
Answer:see explanationStep-by-step explanation:To find the second and fifth terms substitute n = 2 and n = 5 into the rule, that is(a)[tex]a_{2}[/tex] = 3(2)² - 1 = (3 × 4) - 1 = 12 - 1 = 11(b)[tex]a_{5}[/tex] = 3(5)² - 1 = (3 × 25) - 1 = 75 - 1 = 74Thus the second term is 11 and the fifth term is 74